6x=2x^2-40

Solution for 6x=2x^2-40 equation:

6x=2x^2-40

We move all terms to the left:

6x-(2x^2-40)=0

We get rid of parentheses

-2x^2+6x+40=0

a = -2; b = 6; c = +40;
Δ = b2-4ac
Δ = 62-4·(-2)·40
Δ = 356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{356}=\sqrt{4*89}=\sqrt{4}*\sqrt{89}=2\sqrt{89}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{89}}{2*-2}=\frac{-6-2\sqrt{89}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{89}}{2*-2}=\frac{-6+2\sqrt{89}}{-4}
$